Percentages (O-level chemistry)

Percentages (O-level chemistry)

PERCENTAGE

We calculate the percentage of an element in a compound if we know the relative atomic masses e.g.

 

Example 1

 

What is the percentage of Fe in Iron II sulphate (FeSO4. 7H2O)

 

[Fe = 56, S = 32, 0 = 16, H = 1]

 

Solution:

R.F.M of FeSO4.7H2O

Fe   + S   + 4O + 7 (2H + O)  

 

56 + 32 + (4 x 16) + 7(2 + 16)

                        =          278

 

There are 56 parts of iron in 278 parts of the compound

Example 2

What is the percentage of nitrogen in ammonium sulphate? [(NH4)2 SO4

(N = 14, H = 1, S = 32 0 = 16)                                                         

 

Solution:

R.F.M of (NH4)2SO4   = 2(14 + 4)     + 32 + 16 X 4

                                       36 + 32   + 64

                                      = 132

Also, watch this

For revision Questions dawnload the PDF beloww

Mole concept (percentages)

Sponsored by The Science Foundation College + 256 753 802709

Compiled by Dr. Bbosa Science

 

 

CATEGORIES
TAGS
Share This

COMMENTS

Wordpress (2)
  • comment-avatar
    Gibra 10 months

    Great work

    • comment-avatar
      Nelson Oliha Arkangelo Abel 3 weeks

      Well organized notes!

      Good for students’ self revision.

      Thanks for the great work fellow academic Liberators

  • Disqus (0 )