Distribution law/partition coefficient (A -level physical chemistry)
Distribution Law:
States that a solute distributes itself between immiscible solvents such that a constant temperature and pressure the ratio of its concentrations in the two solvents is constant at a given temperature
That is,
If C is the solute, and A and B are the immiscible solvents, them
Limitations
- Solute should be in the same molecular state in both solvents
- Temperature should be constant
- None of the solvent should be saturated / solutions should be dilute.
Definition
Partition Coefficient or distribution constant is ratio of the concentration of the solute in immiscible solvents at equilibrium.
Experiment to determine partition coefficient
- By finding the ration of concentrations of a solute in one solvent over the concentration a solute in another immiscible solvent at equilibrium.
- The concentration of a solute in a solvent may be obtained by titration or other reliable method.
Application of distribution laws
1. Extraction of organic compound
Example 1
A solution of 6g of a substance X in 50cm3 of aqueous is in equilibrium at room temperature with an ethereal solution of X containing 108g of x in 100cm3.
Calculate the mass of x that could be extracted by shaking 100cm3 of an aqueous solution containing 10g of X with:
- 100cm3 of ether
- 50cm3 of ether twice at room temperature.
Solution
First determine the partition constant Kd
- Study of complexes
- The moles of a ligand that forms a complex with a metal ion = to the total moles of ligand in aqueous solution – moles of ligand that did not form a complex
- The mole of a ligand that did not a complex can be found partition coefficient, Kd
- The moles of ligand that form a complex per mole of a metal cation is obtained by division of the moles that formed a complex by the moles of metal ions
Example 2
Excess ammonia was shaken with equal volume of trichloromethane
And a 0.05M aqueous solution of copper (II) ions to form a complex (Cu(NH3)n]2+. At equilibrium, the concnentrations of ammonia in the trichloromethane and in the aqueous layer were 0.021moll-1 and 0.725moll-1 respectively.
(the partition coefficient, KD, of ammonia between water and trichloromethane is 25)
Calculate:
(i) The concentration of free ammonia in aqueous layer
(ii) The concentration of ammonia that formed the complex with copper ions
(iii) The values of n in the complex
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