Reaction of lead II chloride with sodium hydroxide solution

Lead II chloride reacts with sodium hydroxide solution to form lead (II) hydroxide which dissolves in excess sodium hydroxide to form sodium plumbate (II)

PbCl₂ (s) + 2OH^–(aq) → Pb(OH)₂(s) + 2Cl^–(aq)

Then

Pb(OH)₂(s) + 2OH^–(aq) → Pb(OH)₄^2-(aq)