Reaction of lead II chloride with sodium hydroxide solution
Lead II chloride reacts with sodium hydroxide solution to form lead (II) hydroxide which dissolves in excess sodium hydroxide to form sodium plumbate (II)
PbCl2 (s) + 2OH–(aq) → Pb(OH)2(s) + 2Cl–(aq)
Then
Pb(OH)2(s) + 2OH–(aq) → Pb(OH)42-(aq)
CATEGORIES Inorganic chemistry
TAGS Dr. Bbosa Science
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