Show that a ray of light passing through layers of transparent media separated by parallel boundaries, nsin i = a where a is a constant and n is the refractive index of the medium containing angle i.

Show that a ray of light passing through layers of transparent media separated by parallel boundaries, nsin i = a where a is a constant and n is the refractive index of the medium containing angle i.

Show that a ray of light passing through layers of transparent media separated by parallel boundaries,

nsin i = a where a is a constant and n is the refractive index of the medium containing angle i.

Solution

Consider a ray of light moving from air through a series of media 1, 2 and then finally emerge into air as shown.

At air – medium 1 interface, Snell’s law gives  (sin i /sin i1) = n1

=> Sin ia = n1sin i1 …………………………….. (i)

At air – medium 2 interface, Snell’s law gives (sin i /sin i2) = n2

=> Sin ia = n2sin i2 …………………………….. (ii)

Equating equation (i) and (ii) gives

n1 sin i1  =  n2 sin i2.

therefore,  n sin i = a constant.

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    Edrine 10 months

    Nice explainations

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