Show with the aid of a ray diagram that the radius of curvature of a concave mirror is twice the focal length of the mirror.
Show with the aid of a ray diagram that the radius of curvature of a concave mirror is twice the focal length of the mirror.
Consider the reflection of a paraxial ray, AX, parallel to the principal axis of a concave mirror as shown.
Taking FP = focal length and C = center of curvature, then, CX is the normal to the mirror surface and CP is the radius of curvatures.
since i and 2i are small angles;
tan i≈ i = XP/ CP …………………..(i)
tan 2i ≈ 2i = XP/CP ……………… (ii)
Combining (i) and (ii)
2(XP/CP) =XP/FP
Dividing buy XP on both sides
2/CP = 1/ FP or CP =2FP
But CP = r and FP = f
therefore, r = 2f
Thus, the radius of curvature is twice the focal length
CATEGORIES Physics questions and answers
Thanks for the work but I think the second equation should be tan2i≈2i=XP/FP